Explanation:
This is a combinations question.
The number of ways you can combine n objects taken r at a time is given by:
^nC_r=\frac{n!}{r!(n-r)!}
Although there are 52 cards in a deck, only \frac{52}{4}=13 of them are hearts. So in this example n=13 and r=5.
^{13}C_5=\frac{13!}{5!\times(13-5)!}=\frac{13!}{5!\times(8)!} \\ =\frac{13\times12\times11\times10\times9}{5\times4\times3\times2}
=13\times3\times11\times3=1287
So, the number of hands possible consisting of only hearts is 1287.
Q-How many four-digit numbers can be formed from the digits 1, 3, 4, 5, 6 and 7, if repetition of the digit is not allowed?… and if the numbers are greater than 5,000?
Solution
We have 6 digits available.
There are 3 ways to fill the first digit (5,6,7)
5 ways to fill the second digit
4 ways to fill the third digit
3 ways to fill the fourth digit
3×5×4×3=180
180, four-digit numbers if the numbers are greater than 5,000 can be formed from the digits 1, 3, 4, 5, 6 and 7 where the digits are used repetition is not allowed
The first digit can be selected in six ways; and another digit can also be selected in six ways
Including the third digit increases the number of ways to
36 \times 6= 216.
Note: If repetition is not allowed, the number of ways will be
6 \times 5 \times 4 = 120
Q- How many 5 digits numbers can be formed from 1, 2, 3, 4, 5 if repetition of the digit is not allowed
Total Number of 5 digits Numbers which can be formed by numbers 1,2,3,4,5 (without repeating digits)
= 5\times4\times3\times2 = 5! = 120.
Q- How many numbers can be formed from 1, 2, 3, 4, 5 if repetition of the digit is not allowed
Single digit | 5= \;5\;ways |
Two digit | 5\times4=\;20\; ways |
three digit | 5\times4\times 3= \;60\; ways |
four digit | 5\times4\times 3\times2 =\;120\; ways |
five digits | 5\times4\times 3\times2\times1= \;120\; ways |
the number of total numbers = 5 + 20 + 60 + 120 + 120=325
How many 5 digit numbers can be formed using (0-9) 0,1,2,3,4,5,6,7,8,9
10\times10\times10\times10\times10=10^5=100000
The number of signals that can be sent by 5 flags of different colors taking one or more at a time is
Solution
Number of signals using one flag
{\color{Blue} ^{5}\textrm{P}_1}= 5
Number of signals using two flags
{\color{Blue} ^{5}\textrm{P}_2} = 20
Number of signals using three flags
{\color{Blue} ^{5}\textrm{P}_3} = 60
Number of signals using four flags
{\color{Blue} ^{5}\textrm{P}_4} = 120
Number of signals using five flags
{\color{Blue} ^{5}\textrm{P}_5} = 120
Therefore, the total number of signals using one or more flags at a time is
5 + 20 + 60 + 120 + 120= 325
Q-How many four-digit numbers can be formed from the digits 1, 3, 4, 5, 6 and 7, if repetition of the digit is not allowed?… and if the numbers are greater than 5,000?
Solution
We have 6 digits available.
There are 3 ways to fill the first digit (5,6,7)
5 ways to fill the second digit
4 ways to fill the third digit
3 ways to fill the fourth digit
3×5×4×3=180